Tell Me Something About Yourself - Interview Answers.

Try to introduce some of your most important employment-oriented skills as well as your education and accomplishments to the interviewer. Answer to this question is very important because it positions you for the rest of the interview. That's why this statement is often called the " Positioning Statement".

One should take the opportunity to show his/her communication skills by speaking clearly and concisely in an organized manner. Since there is no right or wrong answer for this question hence it is important to appear friendly.



YOUR ANSWERS CAN BE:

1) I am a person with strong interpersonal skills and have the ability to get along well with people. I enjoy challenges and looking for creative solutions to problems.

2) Besides the details given in my resume, I believe in character values, vision and action. I am quick in learning from mistakes. I am confident that the various tests that you have conducted will corroborate my competencies aptitude and right attitude for th…

Sample C Program To Implement Merge Sort Using Divide & Conquer Strategy.



ALGORITHM:

STEP 1: Start the program.
STEP 2: Read the value of n.
STEP 3: Set a for loop to read the elements of array.
for (i = 0; i < n; i++)
STEP 4: Call the function split ( a, 0, n – 1 )
STEP 5: Print the sorted array a.
STEP 6: Stop the program.


FUNCTION MERGE_SORT (int *a, int low, int high)

STEP 1: Declare the local variable.
STEP 2: If low is less than high then assign the mean value of low and high to mid.
mid = ( low + high ) / 2
STEP 3: Call the function merge_sort ( a, low, mid ).
STEP 4: Call the another function merge_sort ( a, mid + 1, high ).
STEP 5: Call the function combine ( a, low, mid, high ).


FUNCTION SPLIT(int *c, int first, int last)

STEP 1: Declare the local variables.
STEP 2: Set the while loop till the condition i <= mid && j <= high is failed.
STEP 3: Check whether a[i] < a[j]
STEP 4: If so the assign the value of a[j] to temp[k] and increment j and k
temp[k] = a[i]
j++
k++
STEP 5: Else assign a[j] to temp[k] and then increment j and k
temp[k]=a[j]
j++
k++

STEP 6: Set another while loop till i is less than mid.
STEP 7: Assign the value of a[i] to temp[k]
temp[k] = a[i]
j++
k++
STEP 8: Set another while loop till j is greater than mid.
STEP 9: Assign the value of a[j] to temp[k]
temp[k] = a[j]
j++
k++
STEP 10: Construct a for loop for k.
for(k = low; k <= high; k++)

STEP 11: Assign the value of temp[k] to a[k].
a[k] = temp[k]


SAMPLE PROGRAM:

#include<stdio.h>
#include<conio.h>

void split(int *, int, int);
void merge(int *, int, int, int, int);
int a[25], b[25];

void main()
{

int i, n;
clrscr();
printf(" Enter the limit ");
scanf(" %d ", &n);

printf(" \n Enter the elements ");

for(i = 0; i < n; i++)
scanf(" %d ", &a[i]);

split(a, 0, n – 1 );
printf("\n The sorted list is: ");

for(i = 0 ;i < n; i++)
printf(" \n %d ", a[i]);

getch();

}


void split(int *c, int first, int last)
{

int mid;
if(first < last)
{
mid = ( first + last ) / 2;

split(c, first, mid);
split(c, mid+1, last);

merge(c, first, mid, mid + 1, last);

}
}


void merge(int *a, int f1, int l1, int f2, intl2)
{

int i, j, k = 0;
i = f1;
j = f2;
while(i <= l1&& j <= l2)
{

if(a[i] < a[j])
b[k] = a[i++];
else
b[k] = a[j++];

k++;
}

while(i <= l1)
b[k++] = a[i++];

while(j <= l2)
i = f1;

j = 0;

while(i <= l2 && j < k)
a[i++] = b[j++]

}



OUTPUT:

Enter the limit: 6
Enter the elements
23
45
89
98
09
65
The Sorted List is: 09 23 45 65 89 98




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Comments

  1. this code is not working...
    please fix it

    ReplyDelete
  2. the code has a bug at after scanning of second array

    ReplyDelete

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